1.

Find the value of k for which the given quadratic equation x2-4x+k=0 has distinct real roots.

Answer» For distinct real roots the discriminant should be >0

(-4)^2-4×1×k>0

=> 4k < 16

=> k<4

x2 - 4x + k = 0 

Here, a= 1, b = -4 and c = k 

Since, D = b2 - 4ac 

therefore, (-4)2 - 4(1)(k) > 0 [ Since , there are two distinct roots] 

16 - 4k > 0 

16 > 4k 

16/4 > k 

k < 4 

Hence, when k < 4, then the quadratic equation x2 – 4x + k = 0 has distinct real roots. 



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