Fluorine does not form oxyacid, but other halogens do. Why? (b) Both ` – InterviewSolution

InterviewSolution

1.	Fluorine does not form oxyacid, but other halogens do. Why? (b) Both `NO` and `ClO_(2)` are odd electron species. `NO` dimeries but `ClO_(2)` does not . Why?
Answer» (a) In oxy-acids the central elements always exhibits positive oxidation states. Fluorine , being the most electronegative , never shows positive oxidation states, hence `F` does not form oxy-acids. Other halogens have the tendency to show positive oxidation states and hence form oxy-acids. (b) In `NO` the size of nitrogen atom is small and the odd electrons is attracted by only oxygen atom while in `ClO_(2)` the size of chlorine atom is comparatively large and an odd electron is attracted by two oxygen atoms.As a result, the odd electron on `N` in `NO` is localised while the odd electron on chlorine in `ClO_(2)` is delocalised. Thus, `NO` has a tendency to dimerise but `ClO_(2)` does not.

Discussion

No Comment Found

Related InterviewSolutions

Nitric oxide, though an odd electron molecule, is diamagenetic in liquid state.
In the reaction: `3Br_(2)+6OH^(Theta)rarr 5Br^(Theta)+BrO_(3)^(Theta)+3H_(2)O,Br_(2)` isA. OxidisedB. ReducedC. DisintegratedD. Disproportionted
Give balanced equations for the following : Phosphorous reacts with nitric acid to give equimolar ratio of nitric oxide and nitrogen dioxide.
(a) Though nitrogen exhibits `+5` oxidation state, it does not form pentahalide. Give reason. (b) `PH_3` has lower boiling point than `NH_3`. Why ?
In white phosphorous `/_ PPP = 90^@`.
Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen ?A. `HNO_3, NO, NH_4 Cl, N_2`B. `HNO_3, NO, N_2, NH_4 Cl`C. `HNO_3, NH_4 Cl, NO,N_2`D. `NO,HNO_3, NH_4 Cl, N_2`
Why commercial `HNO_3` is generally yellow in colour ?
The product formed in the reaction of `SOCl_2` (thionyl chloride) with white phosphorous is.A. `PCl_3`B. `SO_2 Cl_2`C. `SCl_2`D. `POCl_3`
Concentrated `HNO_3`, upon long standing, turns yellow-brown due to the formation ofA. `NO`B. `NO_2`C. `N_2 O`D. `N_2 O_4`
When sulphur is boiled is boiled with `Na_2 SO_3`, a compound `(X)` is produced, `(X)` with excess of `AgNO_3` solution gives a compound `(Y)` which is soluble in water and produces a black coloured sulphide `(Z)`. Identify compounds `(X),(Y)` and `(Z)`.