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For a linear harmonic oscillator, its potential energy, kinetic energy and total energy given by `E_(P), K_(K) and E_(T)` respectively. Its maximum acceleration is given byA. `sqrt((2E_(P))/(m))`B. `sqrt((2E_(K))/(m))`C. `sqrt((2E_T)/(mA))`D. `(2E_T)/(mA)` |
Answer» Correct Answer - D In a SHM. Maximum acceleration = `omega^(2)` A and Total energy `E = (1)/(2)m omega^(2)A^(2)=(1)/(2)m A(omega^(2)A)` `therefore" "omega^(2)A = (2E)/(mA)`= Maximum acceleration |
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