For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume is TV^(x) = constant, where x is

For a monoatomic ideal gas undergoing an adiabatic change, the relatio

1.	For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume is TV^(x) = constant, where x is
Answer» <html><body><p>`7//<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`<br/>`2//5`<br/>`2//3`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//3`</p>Solution :For an adiabatic change, `TV^(gamma - 1)` = <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> …(i) <br/> `TV^(x)` = constant (Given) ….(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <br/> <a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> (i) and (ii), we get `x = gamma - 1` <br/> For a monatomic gas, `gamma = (5)/(3) :. x = (5)/(3) - 1 = (2)/(3)`</body></html>