For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, distance between two consecutive nodes is ...... m.

For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, dist

1.	For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, distance between two consecutive nodes is ...... m.
Answer» 4 2 1 8 Solution :Comparing GIVEN equation with `y = 2A SIN (kx) COS (omega t), ` we get `k = (PI)(4)` `therefore (2pi)/(lamda) = (pi)/(4) implies lamda = 8 m` Required distance `= (lamda)/(2) = (8)/(2) = 4 m`