For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, distance between two consecutive nodes is ...... m.

For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, dist

1.	For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t )metre, distance between two consecutive nodes is ...... m.
Answer» <html><body><p>4<br/>2<br/>1<br/>8</p>Solution :Comparing <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> equation with `y = <a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a> <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> (kx) <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> (omega t), ` we get `k = (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)(4)` <br/> `therefore (2pi)/(lamda) = (pi)/(4) implies lamda = 8 m` <br/> Required distance `= (lamda)/(2) = (8)/(2) = 4 m`</body></html>