1.

For a two step reaction. AhArrR+B""R+Coverset(k_(2))toP (where, R is a reactive intermediate whose concentration is maintained at some low steady state throughout the reaction). If the concentration of C is very high then the order of reaction for formation of "P" is

Answer»

2
0
1
`1//2`

SOLUTION :Rate law `=(DP)/(dt)=K_(2)[R][C]`
at STEADY STATE `(d[R])/(dt)=0`
`(d[R])/(dt)=K_(1)[A]-K_(2)[R][B]-K_(2)[R][C]=0`
`K_(1)[A]={K_(2)[B]+K_(2)[C]}[R]`
`[R]=(K_(1)[A])/(K_(2){[B]+[C]})`
Rate `=K_(2)XX(K_(1))/(K_(2))([A])/([B]+[C])xx[C]`
`ul(K_(1)[A])`
`=([B])/([C])+1`
where C is very high
Rate `=K_(1)[A]`
`:.` order of reaction` = 1 ""]`


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