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For any positive integer m ______ is divisible by 4.(a) 5m^2 + 2(b) 3m + 1(c) m^2 + 3(d) m^3 + 3mI had been asked this question during an interview.I want to ask this question from Principle of Mathematical Induction topic in division Induction and Recursion of Discrete Mathematics

Answer» RIGHT ANSWER is (d) m^3 + 3m

Best explanation: The required answer is, m^3 + 3m. Now, by INDUCTION hypothesis, we have to prove for m=K, k^3+3k is divisible by 4. So, (k + 1)^3 + 3 (k + 1) = k^3 + 3 k^2 + 6 k + 4

= [k^3 + 3 k] + [3 k^2 + 3 k + 4] = 4M + (12k^2 + 12k) – (8K^2 + 8k – 4), both the terms are divisible by 4. Hence (k + 1)^3 + 3 (k + 1) is also divisible by 4 and hence it is proved for any integer m.


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