For CaOCl2, the rate of evaporation is given by W = 325p^0.5M/T^1.5 g/liter, where T is in K, p in mm Hg, and M is molecular weight, if its pressure is given by ln p* = 25 – 2700/T, what is the evaporation rate at T = 150 K?(a) 256 g/liter(b) 499 g/liter(c) 571 g/liter(d) 744 g/literI had been asked this question during a job interview.My doubt is from Modeling and Predicting Vapor Pressure in chapter Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

For CaOCl2, the rate of evaporation is given by W = 325p^0.5M/T^1.5 g/

1.	For CaOCl2, the rate of evaporation is given by W = 325p^0.5M/T^1.5 g/liter, where T is in K, p in mm Hg, and M is molecular weight, if its pressure is given by ln p* = 25 – 2700/T, what is the evaporation rate at T = 150 K?(a) 256 g/liter(b) 499 g/liter(c) 571 g/liter(d) 744 g/literI had been asked this question during a job interview.My doubt is from Modeling and Predicting Vapor Pressure in chapter Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering
Answer» Right option is (d) 744 g/liter For EXPLANATION I would SAY: ln p* = 25 – 2700/150 = 7, => p = 1096.6 mm Hg, => W = 325(1096.6)^0.5*127/150^1.5 = 744 g/liter.

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