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For `d` electron, the orbital angular momentum isA. `sqrt(6)((h)/(2pi))`B. `sqrt(2)((h)/(2pi))`C. `((h)/(2pi))`D. `2((h)/(2pi))` |
Answer» Correct Answer - A According to quantum mechanics, the orbital angular momentum is given as `sqrt(l(l+1)).(h)/(2pi)` For a `d` electron, `l = 2`, thus, `mvr = sqrt(2(2+1)) (h)/(2pi) = sqrt(6) ((h)/(2pi))` |
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