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For p>0, a vector →V2=2^i+(p+1)^j is obtained by rotating the vector →V1=√3p^i+^j by an angle θ about origin in counter clockwise direction. If tanθ=(α√3−2)(4√3+3), then the value of α is equal to

Answer» For p>0, a vector V2=2^i+(p+1)^j is obtained by rotating the vector V1=3p^i+^j by an angle θ about origin in counter clockwise direction. If tanθ=(α32)(43+3), then the value of α is equal to


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