For reaction AtoB, the rate constant k_(1)=A_(1)e^(-Ea)//RT and for the reaction PtoQ, the rate constant k_(2)=A_(2)e^(-Ea_(2))//RT. If A_(1)=10^(8),andEa_(1)=600"cal/mol",Ea_(2)=1200"cal/mol", then the temperature at which k_(1)=k_(2) is (R=2cal/K-mol)

For reaction AtoB, the rate constant k_(1)=A_(1)e^(-Ea)//RT and for th

1.	For reaction AtoB, the rate constant k_(1)=A_(1)e^(-Ea)//RT and for the reaction PtoQ, the rate constant k_(2)=A_(2)e^(-Ea_(2))//RT. If A_(1)=10^(8),andEa_(1)=600"cal/mol",Ea_(2)=1200"cal/mol", then the temperature at which k_(1)=k_(2) is (R=2cal/K-mol)
Answer» 600 K `300xx4.606` K `(300)/(4.606)K` `(4.606)/(600)K` SOLUTION :`A_(1)e-Ea_(1)//RT=A_(2)e-Ea_(2)//RT` `(A_(2))/(A_(1))=e(Ea_(2)-Ea_(1))//RT` `10^(2)="Exp"{(600)/(RT)}"R=2cal/K-mol"` `2" ln "10=(600)/(2T)` `T={(300)/(2xx2.303)}K""]`

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For reaction AtoB, the rate constant k_(1)=A_(1)e^(-Ea)//RT and for the reaction PtoQ, the rate constant k_(2)=A_(2)e^(-Ea_(2))//RT. If A_(1)=10^(8),andEa_(1)=600"cal/mol",Ea_(2)=1200"cal/mol", then the temperature at which k_(1)=k_(2) is (R=2cal/K-mol)

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