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For the arrangement shown in the figure, the switch is closed at `t = 0`. `C_2` is initially uncharged while `C_1` has a charge of `2muC` (a) Find the current comingn out of the battery just after the switch is closed. (b) Find the charge on the capacitors in the steady state condition. |
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Answer» Correct Answer - B At `t=0`, equivalent resistance of an uncharged capacitor is zero and a charged capacitor is like a bttery of emf = potential difference across the capacitor. a. `V_(C_1)=q_1/C_1=2V` `:.` Net emf of the circuit `=9-2=7V` or `92=11V` Net resistance `=30+(30xx60)/(30+60)=50Omega` `:.` Current at `t=0` would be `i_0=7/50A` or `11/50A` b. In steady state no current will flow through the circuit `C_2` will therefore be short circuited, while `PD` across `C_1` will be 9 V `:. Q_2=0 and Q_1=9muC` |
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