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InterviewSolution
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For the coagulation of `100 mL` of arsenious sulphite `sol,5 mL` of `1 M NaCl` is required. What is the flocculaton value of `NaCl`? |
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Answer» `5mL` of `1MNaCl` contains `NaCl=(1)/(1000)xx5mol=5m mol` Thus, `100mL` of `As_(2)S_(3)sol` require `NaCl` for complete, coagulation `=5m mol` `:.` 1L, i.e., `1000mL` of the sol requires `NaCl` for complete, coagulation `=50m mol` Therefore, the flocculation value of `NaCl=50` `5mL` of `1MNaCl` contains `NaCl=(1)/(1000)xx5mol=5m mol` Thus, `100mL` of `As_(2)S_(3)sol` require `NaCl` for complete, coagulation `=5m mol` `:.` 1L, i.e., `1000mL` of the sol requires `NaCl` for complete, coagulation `=50m mol` Therefore, the flocculation value of `NaCl=50` |
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