InterviewSolution
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InterviewSolution
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For the following electrochemical cell at 298 K `Pt(s)|H_(2),(g,1" bar")|H^(+)(aq,1M)||M^(4+)(aq)|M^(2+)(aq)|Pt(s)` `E_(cell)=0.092V` when `([M^(2+)(aq)])/([M^(4+)(aq)])=10^(x)` Given `E_(M^(4+)//M^(2+))^(@)=0.151V,2.303(RT)/(F)=0.059V` the value of x isA. `-2`B. `-1`C. `1`D. `2` |
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Answer» Correct Answer - D The reactions occurring in the cell are At anode: `H_(2)(g)to2H^(+)(aq)+2e^(-)` `underline("At cathode: "M^(4+)(aq)+2e^(-)toM^(2+)(aq))` Overall reaction: `H_(2)(g)+M^(4+)(aq)toM^(2+)(aq)+2H^(+)(aq)` `E_(cell)=E_(cell)^(@)-(0.059)/(2)"log"([M^(2+)][H^(+)]^(2))/([M^(4+)])` `E_(cell)^(@)-E_(M^(4+)//M^(2+))^(@)-E_(H^(+)//H_(2))^(@)` `=0.151-0=0.151V` `therefore0.092=0.151-(0.059)/(2)log(10^(x)xx1^(2))` or `0.092=0.151-0.0295log10^(x)` or `0.0295log10^(x)=0.151-0.092=0.059` or `log10^(x)=(0.059)/(0.0295)=2` `therefore10^(x)`=Antilog `2=10^(2)thereforex=2` |
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