For the reaction :2 Ag+ + 2 Hg → 2 Ag + Hg22+E˚ Ag+/Ag = 0.80 V E˚

1.	For the reaction :2 Ag+ + 2 Hg → 2 Ag + Hg22+E˚ Ag+/Ag = 0.80 V E˚ Hg22+/Hg = 0.79 V Predict the direction in which the reaction will proceed if :[Ag+] = 10-1mol/h [Hg2+] = 10-3mol/h
Answer» Cell reaction is : 2 Ag⁺ + 2 Hg → 2 Ag + Hg₂²⁺ E_cell = E˚_cell – 0.0591/2 log [Hg₂²⁺]/ [Ag⁺]² = (0.80 V -0.79 V) - 0.0591/2 log 10^-3/(10^-1)² = 0.01 V- 0.0591/2 (-1) = 0.01 + 0.0295 = 0.0395 V Since E_cell is positive, the reaction will be spontaneous in the forward direction.

For the reaction :2 Ag+ + 2 Hg → 2 Ag + Hg22+E˚ Ag+/Ag = 0.80 V E˚ Hg22+/Hg = 0.79 V Predict the direction in which the reaction will proceed if :[Ag+] = 10-1mol/h [Hg2+] = 10-3mol/h

Answer»

Cell reaction is :

2 Ag⁺ + 2 Hg → 2 Ag + Hg₂²⁺

E_cell = E˚_cell – 0.0591/2 log [Hg₂²⁺]/ [Ag⁺]²

= (0.80 V -0.79 V) - 0.0591/2 log 10^-3/(10^-1)² = 0.01 V- 0.0591/2 (-1) = 0.01 + 0.0295

= 0.0395 V

Since E_cell is positive,

the reaction will be spontaneous in the forward direction.

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For the reaction :2 Ag+ + 2 Hg → 2 Ag + Hg22+E˚ Ag+/Ag = 0.80 V E˚ Hg22+/Hg = 0.79 V Predict the direction in which the reaction will proceed if :[Ag+] = 10-1mol/h [Hg2+] = 10-3mol/h

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