For the reaction aA+ bB → rR, which of the following is true?(a) \(\frac{-r_A}{a}\)=\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(b) \(\frac{-r_A}{a}\) ≥\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(c) \(\frac{-r_A}{a}\)=\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(d) \(\frac{-r_A}{a}\)≤\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)I had been asked this question in an interview.My enquiry is from Reaction Rates in portion Basic Concepts of Chemical Reaction Engineering

For the reaction aA+ bB → rR, which of the following is true?(a) \(\

1.	For the reaction aA+ bB → rR, which of the following is true?(a) \(\frac{-r_A}{a}\)=\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(b) \(\frac{-r_A}{a}\) ≥\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(c) \(\frac{-r_A}{a}\)=\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)(d) \(\frac{-r_A}{a}\)≤\(\frac{-r_B}{b}\) ≤ \(\frac{r_R}{r} \)I had been asked this question in an interview.My enquiry is from Reaction Rates in portion Basic Concepts of Chemical Reaction Engineering
Answer» Correct answer is (c) \(\frac{-r_A}{a}\)=\(\frac{-r_B}{B}\) ≤ \(\frac{r_R}{r} \) The EXPLANATION is: The rates of degradation of reactants and formation of product are RELATED to each other as \(\frac{-r_A}{a} = \frac{-r_B}{b} = \frac{r_R}{r} \), where a, b and c DENOTE the stoichiometry. The rate of disappearance of any reactant in TURN is the rate of formation of products.

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