InterviewSolution
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InterviewSolution
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For the reaction CH_(3)COCH_(3)+Br_(2)overset(H^(+))toCH_(3)COCH_(2)Br+H^(+)+Br^(-) the following data was collected {:(["Acctone"],[Br_(2)],[H^(+)],"Rate of reaction "(Ms^(-1)),),(" "0.15,0.025,0.025," "6xx10^(-4),),(" "0.15,0.050,0.025," "6xx10^(-4),),(" "0.15,0.025,0.050," "12xx10^(-4),),(" "0.20,0.025,0.025," "8.0xx10^(-4),):} Calculate order of the reaction w.r.t. CH_(3)COCH_(3)andBr_(2) |
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Answer» Solution :`"RATE"=k."[ACETONE]"^(x).[Br_(2)]^(y).[H]^(z)` <BR> `6xx10^(-4)=k.(0.15)^(x)(0.025)^(y)(0.025)^(z)`. . . .(i) `6xx10^(-4)=k.(0.15)^(x)(0.050)^(y)(0.025)^(z)`. . . .(ii) `12xx10^(-4)=k.(0.15)^(x)(0.025)^(y)(0.050)^(z)`. . . .(iii) `8xx10^(-4)=k.(0.20)^(x)(0.025)^(y)(0.025)^(z)`. . . .(iv) (i) `divide` (ii), `1((0.025)/(0.050))^(y)` y=0, hance rate does not depend upon the CONCENTRATION of `Br_(2)`. (i) `divide` (iii), `(6)/(12)=((0.025)/(0.050))^(z),(1)/(2)=((1)/(2))^(z)` `:.z=1` (i) `divide` (iv), `(3)/(4)=((3)/(4))^(x)` `:.x=1""]` |
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