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For three events A,B and CP (exactly one of the events A or B occurs) = P(exactly one of the events B or C occurs) = P(exactly one of the events C ir A occurs) = P and P(all the three events occur simultaneously) =P^(2), where 0ltplt(1)/(2) Then the probability of at least one of the three events A,B and C occuring is : |
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Answer» `(3p+2p^(2))/(2)` SIMILARLY for B or C , C or A Adding all THREE, we get, `P(A)+P(B)+P(C )-P(A nn B)-P(B nn C)-P(C nn A)=(3p)/(2)` `P(A uu B uu C)=(3p)/(2)+p^(2)` |
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