1.

Four moels of a perfect gas is heated to increase its temperature by 2^(0)C absorbsheat of 40 cal at constant volume. If the same gas is heated at constant pressure find the amount of heat supplied. (R = 2 cal/molK).

Answer»

Solution :Number of moles n = 4
Change in TEMPERATURE`Deltat=2`
Heat ENERGY absorbed `dQ=40` cal.
GAS constant `R = 2` cal/mole K
Heat energy absorbed at constant pressure
`dQ = dU +dW` per mole per kelvin.
But `dU = C_(v)DT and dW = P dV`
`C_(p)=C_(v) +R`Multiply with n.dT
`nC_(p)dT=nC_(v)dT +nRdT`
`nC_(p)dT =` Heat energyabsorbed at constant pressure by n moles of gas.
`nC_(v)dT=dU =`Heat energy absorbed at constant volume.
`:.dQ=dU+nRdT =40+4xx2xx2=56`cal
Heat energy absorbed at constant presure when 4 moles of air is heated through `2^(0)=56`cal.


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