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Four moels of a perfect gas is heated to increase its temperature by 2^(0)C absorbsheat of 40 cal at constant volume. If the same gas is heated at constant pressure find the amount of heat supplied. (R = 2 cal/molK).

Answer» <html><body><p></p>Solution :Number of moles n = 4 <br/> Change in <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>`Deltat=2` <br/> Heat <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> absorbed `dQ=40` cal. <br/> <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> constant `R = 2` cal/mole <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> <br/> Heat energy absorbed at constant pressure <br/> `dQ = dU +dW` per mole per kelvin. <br/> But `dU = C_(v)<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a> and dW = P dV` <br/> `C_(p)=C_(v) +R`Multiply with n.dT <br/> `nC_(p)dT=nC_(v)dT +nRdT` <br/> `nC_(p)dT =` Heat energyabsorbed at constant pressure by n moles of gas. <br/> `nC_(v)dT=dU =`Heat energy absorbed at constant volume. <br/> `:.dQ=dU+nRdT =40+4xx2xx2=56`cal <br/> Heat energy absorbed at constant presure when 4 moles of air is heated through `2^(0)=56`cal.</body></html>


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