InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
From the rate expression for the following reactions, determine their order of reaction and the admensions of the rate constants. `i) 3NO (g)to N_(2)O (g)" "Rate=k[NO]^(2)` ii) `H_(2)O_(2)(aq) +3I^(-)(aq)+ 2H^(+) to 2H_(2)O(l)+I_(3)" "Rate =k [H_(2)O_(2)][I^(-)]` iii) `C_(2) H_(5)Cl(g) to C_(2) H_(4)(g) +CO(g)" "Rate =k[CH_(3)CHO]^(3//2)` iv) `C_(2) H_()5) Cl (g) to C_(2)H_(2) to C_(2)H_(4) (g) + HCl(g)" "Rate =k [C_(2)H_(5)Cl]` |
|
Answer» Rate `=k [NO]^(2)` order of reaction =2 units (dimensions) of rate constant `[k] =(Rate)/([NO]^(2))=(mol L^(-1)s^(-1))/((mol L ^(-1))^(2))= mol ^(-1) L s^(-1)` ii) Rate `=k[H_(2)O _(2)] [I^(-)]` order of reaction `=1+1=2` Dimensions of `k =(Rate)/([H_(2)O_(2)][I^(-)])=(mol L^(-1)s^(-1))/((mol L ^(-1))[mol L ^(-1]))= mol ^(-1) L s^(-1)` iii) Rate ` =k [CH_(3) CHO]^(3//2)` order of reaction `=3/2` Dimensions of `k=(Rate)/([CH_(3)CHO]^(3//2))=(mol L ^(-1)s^(-1))/((mol L ^(-1))^(3//2))= mol ^(-1//2)L ^(1//2)s^(-1)` iv) Rate `=k [C_(2) H_(5)Cl]` order of reaction =1 Dimensions of `k=(Rate)/(C_(2) H_(5)Cl)=(mol L ^(-1)s^(-1))/(mol L ^(-1))=s^(-1)` |
|