InterviewSolution
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InterviewSolution
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From the relation R = R0 A1/3 , Where R0 is a constant and A is the mass number of a nucleus show that the nuclear matter density is nearly constant (i.e. Independent of A). |
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Answer» Density of nucleus(p) It is defined as the nuclear mass per unit volume. i.e ρ = \(\frac{mass\,of\,one\,nucleus}{volume\,of\,nucleus}\) = \(\frac{mass\,of\,one\,nucleon\times number\,of\,nucleons}{\frac{4}{3}\pi r^3}\) = \(\frac{1.66\times10^{-27}A}{\frac{4}{3}\pi (R_0A^{1/3})^3}\) = \(\frac{3\times1.66\times10^{-27}A}{4\times3.142\times(1.2\times10^{-15})^3\times A}\) = 2.29 x 1017Kgm-3 Thus the nuclear density is of the order of 1017kgm-3 and is independent of its mass number. Therefore, all nuclei have the same approximate density. |
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