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gamma represents the ratio of two specific heats of a gas. For a given mass of the gas, the change in internal energy when the volume expands from V to 3V to constant pressure P is |
Answer» <html><body><p>`(3PV)/((gamma - <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))`<br/>`(3PV)/((gamma + 1))`<br/>`(2PV)/((gamma + 1))`<br/>`(2PV)/((gamma - 1))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The change in internal energy is `DeltaU = nC_(V)<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> T` <br/> But `C_(V) = (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> )/((gamma - 1)) :. Delta U = (nR Delta T)/((gamma - 1))` <br/> According to the ideal gas <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>, PV = nRT <br/> At constant pressure, `Pdelta V = nR Delta T` <br/> `:. Delta U = (PDelta V)/((gamma - 1)) = (P(3V - V))/((gamma- 1)) = (2PV)/((gamma - 1))`</body></html> | |