Given `E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V` Among the following, the strongest reducing agent is `E_(Cr^(3+)//Cr)^(@)=-0.74V^(x),E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V` `E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(Cl//Cl^(-))^(@)=1.36V` Based on the data given above strongest oxidising agent will beA. `MnO_(4)^(-)`B. `Cl^(-)`C. `Cr^(2+)`D. `Mn^(2+)`

Given `E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+

1.	Given `E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V` Among the following, the strongest reducing agent is `E_(Cr^(3+)//Cr)^(@)=-0.74V^(x),E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V` `E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(Cl//Cl^(-))^(@)=1.36V` Based on the data given above strongest oxidising agent will beA. `MnO_(4)^(-)`B. `Cl^(-)`C. `Cr^(2+)`D. `Mn^(2+)`
Answer» Correct Answer - A In the given reaction, i has been oxidised to 1 and `Cr_(2)O_(7)^(2-)` has been reduced to `Cr^(3+)` `therefore E_("cell")^(@)=E_(Cr_(2)O_(7)^(2-))^(@)-E_(I_(2))^(@)` `therefore 0.79=1.33-E_(I_(2))^(@)` or `E_(I_(2))^(@)=1.33-0.79=0.54`

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