Given, `NH_(3(g))+3Cl_(2(g))iffNCl_(3(g))+3HCl_((g)),-DeltaH_(1)` `N_(2(g))+3H_(2(g))iff2NH_(3(g)),-DeltaH_(2)` `H_(2(g))+Cl_(2(g))iff2HCl_((g)),DeltaH_(3)` The heat of formation of `NCl_(3(g))` in the terms of `DeltaH_(1), DeltaH_(2)` and `DeltaH_(3)` isA. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`C. `DeltaH_(f)=-DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`D. None of these

Given, `NH_(3(g))+3Cl_(2(g))iffNCl_(3(g))+3HCl_((g)),-DeltaH_(1)` `N_(

1.	Given, `NH_(3(g))+3Cl_(2(g))iffNCl_(3(g))+3HCl_((g)),-DeltaH_(1)` `N_(2(g))+3H_(2(g))iff2NH_(3(g)),-DeltaH_(2)` `H_(2(g))+Cl_(2(g))iff2HCl_((g)),DeltaH_(3)` The heat of formation of `NCl_(3(g))` in the terms of `DeltaH_(1), DeltaH_(2)` and `DeltaH_(3)` isA. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`C. `DeltaH_(f)=-DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`D. None of these
Answer» Correct Answer - C Find `(1)/(2)N_(2)+(3)/(2)Cl_(2)rarrNCl_(3),DeltaH_(f)` Multiply Eq. (ii) by 1/2 and add to Eq. (i), Eq. (iii) by 3/2 and subtract from Eq. (i), we get `DeltaH_(f)=-DeltaH_(l)-(DeltaH_(2))/(2)-[+(3)/(2)DeltaH_(3)]` `=-DeltaH_(l)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

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