InterviewSolution
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InterviewSolution
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Given`:` Oxidation`H_(2)O_(2) rarr O_(2)+2H^(o+)+2e^(-)" "E^(c-)=-0.69V,` `2F^(c-)rarr F_(2)+2e^(-)" "E^(c-)=-287V,` Reduction `: H_(2)O_(2)+2H^(o+)+2e^(-) rarr 2H_(2)O" "E^(c-)=1.77V,` 2I^(c-)rarr I_(2)+2e^(-)" "E^(c-)=-0.54V,` Which of the following statements is `//` are correct ?A. `H_(2)O_(2)` behaves as an oxidant for `I_(2)//I^(c-)`B. `H_(2)O_(2)` behaves as an reductant for `I_(2)//I^(c-)`C. `I^(c-)//I_(2)` behaves as an reductant for `H_(2)O_(2)`D. None of these is correct |
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Answer» Correct Answer - a,c Anode `:2I^(c-)rarrI_(2)+2e^(-)+2e^(-),E_(a(o x i d))^(2c-)=-0.535impliesE_(a(Red))^(c-)=+0.535V` Cathode`:H_(2)O_(2)+2H^(o+)+2e^(-)rarr 2H_(2)O,` `E^(c-)._(cell)=(E^(c-)._(cell)-E^(c-)._(a))_(R)=1.77-0.53=+ve` Note that `:` Anode`:H_(2)O_(2) rarr O_(2)+2H^(o+)+2e^(-),` `E^(c_._(a(o x i d))=-0.69V` Cathode`:I_(2)+2e^(-)rarr 2I, " "E^(c-).c_(red))=+0.535V` E^(c-)._(a(red))=+0.69V` `E^(c-)=E^(c-)._(cell)-E^(c-)._(a)=0.535-0.69=-ve` |
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