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Given that √3 is an irrational number, show that (5 +2√3) is an irrational number. |
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Answer» Let 5 + 2√3 be a rational number. 5 + 2√3 = \(\frac{p}{q}\), where p and q are co-prime integers. 2√3 = \(\frac{p}{q}\) - 5 = \(\frac{p - 5q}{q}\) √3 = \(\frac{p - 5q}{2q}\) Here, \(\frac{p - 5q}{2q}\) is rational as p and q are integers. But it is given that √3 is irrational. LHS is irrational and RHS is rational. Which contradicts our assumption that 5 + 2√3 is a rational number. 5 + 2√3 is an irrational number. |
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