InterviewSolution
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InterviewSolution
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Given that for a reaction of order n. the intergrated form of the rate equation is `k= (1)/(t(n-1))[(1)/(C^(n-1))-(1)/(C_(0)^(n-1))]` where `C_(0)` and C are the values after time t. What is the relationship between `t_(3//4)` and `t_(1//2)` where `t_(3//4)` is the time required for C to become `1//4C_(0)-`A. `t_(3//4) = t_(1//2)[2^(n-1) +1]`B. `t_(3//4) =t_(1//2)[2^(n-1)-1]`C. `t_(3//4) =t_(1//2) [2^(n+1) -1]`D. `t_(3//4) =t_(1//2) [2^(n+1)+1]` |
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Answer» Correct Answer - A `t_(3//4)(1)/(K(n-1))[(1)/(((C_(0))/(4))^(n-1))-(1)/(C_(0)^(n-1)]]` `= (1)/(k(n-1)) (4^(n-1)-1)C_(0)^(n-1)` `:. t_(1//2)=(1)/(K(n-1))(2^(n-1)-1)` `So (t_(3//4))/(t_(1//2)) =2^(n-1)+1` |
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