Given that one of the zeroes of the cubic polynomial ax3 + bx2 +

1.	Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is zero, the product of the other two zeroes is(A) (–c/a) (B) c/a(C) 0 (D) (–b/a)
Answer» (B) (c/a) Explanation: According to the question, We have the polynomial, ax³ + bx² + cx + d We know that, Sum of product of roots of a cubic equation is given by c/a It is given that one root = 0 Now, let the other roots be α, β So, we get, αβ + β(0) + (0)α = c/a αβ = c/a Hence the product of other two roots is c/a Hence, option (B) is the correct answer

Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is zero, the product of the other two zeroes is(A) (–c/a) (B) c/a(C) 0 (D) (–b/a)

Answer»

(B) (c/a)

Explanation:

According to the question,

We have the polynomial,

ax³ + bx² + cx + d

We know that,

Sum of product of roots of a cubic equation is given by c/a

It is given that one root = 0

Now, let the other roots be α, β

So, we get,

αβ + β(0) + (0)α = c/a

αβ = c/a

Hence the product of other two roots is c/a

Hence, option (B) is the correct answer