Given the standard electrode potentials,K+/K=−2.93 VAg+/Ag=0.80 VHg2 – InterviewSolution

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1.	Given the standard electrode potentials,K+/K=−2.93 VAg+/Ag=0.80 VHg2+/Hg=0.79 VMg2+/Mg=−2.73 VCr3+/Cr=−0.74 VThe increasing order of reducing power is:
Answer» Given the standard electrode potentials, $K^{+} / K = - 2.93 V A g^{+} / A g = 0.80 V H g^{2 +} / H g = 0.79 V M g^{2 +} / M g = - 2.73 V C r^{3 +} / C r = - 0.74 V$ The increasing order of reducing power is:

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