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`HBr` reacts with `CH_(2)=CH-OCH_(3)` under anhydrous conditions at room temperature to give:A. `CH_(3)CHO` and `CH_(3)Br`B. `BrCH_(2)CHO` and `CH_(3)OH`C. `BrCH_(2)CH_(2)OCH_(3)`D. `CH_(3)-CHBr-OCH_(3)` |
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Answer» Correct Answer - D Addition of a proton to the terminal `CH_(2)` gives a carbocation which is stabilized by + R effect of `OCH_(3)` group. |
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