1.

Heat of dissociation of CH3COOH is 0.005kcal g–1, hence enthalpy change when 1 mole ofCa(OH)2 is completely neutralised by CH3COOHis(a) – 27.4 kcal (b) – 13.6 kcal(c) – 26.8 kcal (d) – 27.1 kcal

Answer» Heat of dissociation of CH3COOH is 0.005
kcal g–1, hence enthalpy change when 1 mole of
Ca(OH)2
is completely neutralised by CH3COOH
is
(a) – 27.4 kcal (b) – 13.6 kcal
(c) – 26.8 kcal (d) – 27.1 kcal


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