Hi ♡Question :-The small gear has 1010 teeth and the big gear has 50

1.	Hi ♡Question :-The small gear has 1010 teeth and the big gear has 5050 teeth. When the small gear rolls around the big gear, how many times will the arrow return to its initial orientation (pointing upward)?Explanation expected.
Answer» $\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$ We are given that the BIG gear has 5050 teeths and the small fear has 1010 teeths. With this the initial orientation of the arrow is given as printing upwards. $\rule{200}2$ Now, we are asked, when the small gear will roll around the big one, how many TIMES the arrow will be in the initial orientation or pointing upwards. $\rule{200}2$ Now, we can say that the number of times the gear will rotate to roll around the big gear, the arrow will pint in the upward DIRECTION that many times. This can be said because only after a single rotation the arrow is going to point upwards. $\rule{200}2$ Now, to finally reach to our answer, we NEED to find the number of times the small gear is going to rotate to roll around the big gear. We KNOW that the number of teeths in a big gear is 5050 and the number of teeths of small gear is 1010. We can say that, $\tt{Number\:of\:rotations=\dfrac{Number\:of\:teeths\:one:big\:gear}{Number\:of\:teeths\:in\:small\:gear}}$ Hence, $\leadsto\tt{Number\:of\:rotations=\dfrac{5050}{1010}}$ $\leadsto\huge{\green{\tt{Number\:of\:rotations=5}}}$ $\rule{200}2$ So, $\leadsto\huge{\green{\tt{Number\:of\:times\:the\:arrow\:will\:point\:upwards=5}}}$ $\rule{200}4$

Hi ♡Question :-The small gear has 1010 teeth and the big gear has 5050 teeth. When the small gear rolls around the big gear, how many times will the arrow return to its initial orientation (pointing upward)?Explanation expected.

Answer»

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

We are given that the BIG gear has 5050 teeths and the small fear has 1010 teeths.

With this the initial orientation of the arrow is given as printing upwards.

$\rule{200}2$

Now, we are asked, when the small gear will roll around the big one, how many TIMES the arrow will be in the initial orientation or pointing upwards.

$\rule{200}2$

Now, we can say that the number of times the gear will rotate to roll around the big gear, the arrow will pint in the upward DIRECTION that many times.

This can be said because only after a single rotation the arrow is going to point upwards.

$\rule{200}2$

Now, to finally reach to our answer, we NEED to find the number of times the small gear is going to rotate to roll around the big gear.

We KNOW that the number of teeths in a big gear is 5050 and the number of teeths of small gear is 1010.

We can say that,

$\tt{Number\:of\:rotations=\dfrac{Number\:of\:teeths\:one:big\:gear}{Number\:of\:teeths\:in\:small\:gear}}$

Hence,

$\leadsto\tt{Number\:of\:rotations=\dfrac{5050}{1010}}$

$\leadsto\huge{\green{\tt{Number\:of\:rotations=5}}}$

$\rule{200}2$

So,

$\leadsto\huge{\green{\tt{Number\:of\:times\:the\:arrow\:will\:point\:upwards=5}}}$

$\rule{200}4$

Hi ♡Question :-The small gear has 1010 teeth and the big gear has 5050 teeth. When the small gear rolls around the big gear, how many times will the arrow return to its initial orientation (pointing upward)?Explanation expected.

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Hi ♡Question :-The small gear has 1010 teeth and the big gear has 5050 teeth. When the small gear rolls around the big gear, how many times will the arrow return to its initial orientation (pointing upward)?Explanation expected. ​

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Hi ♡Question :-The small gear has 1010 teeth and the big gear has 5050 teeth. When the small gear rolls around the big gear, how many times will the arrow return to its initial orientation (pointing upward)?Explanation expected.