1.

how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in order to get a combined resistance of 11/4 ohm? ​

Answer» <html><body><p><strong>Answer:</strong></p><p>ANSWER</p><p>(a) </p><p>Equivalent <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> is </p><p>R </p><p>eq</p><p> </p><p> =R </p><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></p><p> </p><p> +R </p><p>2</p><p> </p><p> +R </p><p>3</p><p> </p><p> =(1+2+3)Ω=6Ω</p><p></p><p>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)</p><p>Current in the circuit is given by I= </p><p>R</p><p>E</p><p> </p><p> </p><p>I= </p><p>6</p><p>12</p><p> </p><p> =2Ω</p><p>Potential drop across 1Ω, V </p><p>1</p><p> </p><p> =IR </p><p>1</p><p> </p><p> =2×1=2V</p><p>Potential drop across 2Ω,V </p><p>2</p><p> </p><p> =IR </p><p>2</p><p> </p><p> =2×2=4V</p><p>Potential drop across 3Ω,V </p><p>3</p><p> </p><p> =IR </p><p>3</p><p> </p><p> =2×3=6V</p></body></html>


Discussion

No Comment Found

Related InterviewSolutions