How do you explain detection of H group basic radicals based on applic

1.	How do you explain detection of H group basic radicals based on application of solubility product.
Answer» Group reagent: HCl → H⁺ + Cl^– ; H₂S ⇌ 2H⁺ + S^2- Radicals: Cu²⁺, Bi²⁺, Sn²⁺ Here HCl is a strong electrolyte under goes complete dissociation where as H₂S is a weak electrolyte under goes partial dissociation and attains equilibrium between it’s ions and molecules. In this solution, because of common ion (H⁺) effect supression of degree of dissociation of H₂S takes place. As a result [S^2-] decreases. Hence the metal radical forms it’s respective sulphides [CuS, SnS, BiS] whose solubility product is less than ionic product. Hence forms precipitate.

How do you explain detection of H group basic radicals based on application of solubility product.

Answer»

Group reagent: HCl → H⁺ + Cl^– ; H₂S ⇌ 2H⁺ + S^2-

Radicals: Cu²⁺, Bi²⁺, Sn²⁺

Here HCl is a strong electrolyte under goes complete dissociation where as H₂S is a weak electrolyte under goes partial dissociation and attains equilibrium between it’s ions and molecules.

In this solution, because of common ion (H⁺) effect supression of degree of dissociation of H₂S takes place. As a result [S^2-] decreases. Hence the metal radical forms it’s respective sulphides [CuS, SnS, BiS] whose solubility product is less than ionic product. Hence forms precipitate.

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