<P>Explanation:

Hint: We solve this problem by using the formula of simple INTEREST.

The formula for the simple interest is given as

SI=P×T×R100

Where P

is the principal amount, T

is the time period and R

is the rate of interest PER annum.

After finding the simple interest for all years from 1 to 6 we create a table of ordered pairs containing the NUMBER of years as x coordinate and simple interest as y co – ordinate so that we can plot them on a graph of a certain scale.

Complete step by step answer:

We are given that the principal amount as

⇒P=8000

We are also given that the rate of interest per annum as

⇒R=5

Let us assume that the time period as T

We know that the formula for the simple interest is given as

SI=P×T×R100

Where, P

is the principal amount, T

is the time period and R

is the rate of interest per annum.

By using the above formula we get the simple interest in terms of time period as

⇒SI=8000×5×T100⇒SI=400T

Now, let us take the time period as 1 year then we get the simple interest of 1 year as

⇒SI1=400×1⇒SI1=400

Now, let us take the time period as 2 years then we get the simple interest for 2 years as

⇒SI2=400×2⇒SI2=800

Now, let us take the time period as 3 years then we get the simple interest for 3 years as

⇒SI3=400×3⇒SI3=1200

Now, let us take the time period as 4 years then we get the simple interest for 4 years as

⇒SI4=400×4⇒SI4=1600

Now, let us take the time period as 5 years then we get the simple interest for 5 years as

⇒SI5=400×5⇒SI5=2000

Now, let us take the time period as 2 years then we get the simple interest for 2 years as

⇒SI6=400×6⇒SI6=2400

Now, let us create a table containing the order pairs containing number of years as x co – ordinate and simple interest as y co – ordinate as follows

Time period (T)

Simple interest (SIi)

Ordered pair(T,SIi)

1 400 (1,400)

2 800 (2,800)

3 1200 (3,1200)

4 1600 (4,1600)

5 2000 (5,2000)

6 2400 (6,2400)

Now, let us consider a scale of the required graph as follows

On X – axis 1 unit equal to 1 year

On Y – axis 1 unit equal to RS. 400

By using the above scale and the coordinate of points in the table we get the graph as

Note:

Students may make mistakes in finding the simple interest of 2, 3, 4, …, 6 years.

By using the simple interest formula for 2 years we get

⇒SI2=8000×5×2100⇒SI2=800

But students may make mistakes in taking the principal value for the time period of 2 years.

The amount after the 1 year is given as

⇒A=8000+400=8400