How many grams of MnO2 are needed to get 36.2g of MnCl2 from the equat – InterviewSolution

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1.	How many grams of MnO2 are needed to get 36.2g of MnCl2 from the equation given below? MnO2 (s)+ 4HCl(aq) →MnCl2 (aq)+2H2O (l)+Cl2(g)87 g 36.5 g 126 g 18 g 71 g 25
Answer» How many grams of ${MnO}_{2}$ are needed to get 36.2g of ${MnCl}_{2}$ from the equation given below? ${MnO}_{2} (s) + 4 HCl (aq) \to {MnCl}_{2} (aq) + 2 H_{2} O (l) + {Cl}_{2} (g) 87 g 36.5 g 126 g 18 g 71 g$ 25

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