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How many moles of mercury will be produced by electrolysing 1.0 M `Hg(NO_(3))_(2)` solution by a current of 2.0 A when passed for 3 hours ? |
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Answer» Quantity of charge passed (Q) `= Ixxt=(2.0 A)xx(3xx60xx60 s)` `=(2.0 Axx10800 s)`=21600 AS=21600 C `Hg(NO_(3))_(2)overset((aq))rarrHg^(2+)(aq)+2 NO_(3)^(-)(aq)` `{:(Hg^(+)(aq)+2e^(-)rarrHg(s)),(" "2xx96500 C" "1 mol):}` When `2xx96500` C is passed, mercury deposited =1 mol When 21600 C is passed, mercury deposited `=(1 mol)xx((21600 C))/((2xx96500 C))=0.112 mol` |
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