How many moles of mercury will be produced by electrolysing 1.0 M `Mg(NO_(3))_(2)` solution with a current of 2.00 A for 3 hours? `[Hg(NO_(3))_(2)=200.6" g "mol^(-1)]`

How many moles of mercury will be produced by electrolysing 1.0 M `Mg(

1.	How many moles of mercury will be produced by electrolysing 1.0 M `Mg(NO_(3))_(2)` solution with a current of 2.00 A for 3 hours? `[Hg(NO_(3))_(2)=200.6" g "mol^(-1)]`
Answer» Correct Answer - 0.112 mole `Hg^(2+)+2e^(-)toHg,Q=2Axx(3xx3600s)=21600C` `2F=2xx96500C` produce `Hg=1` mole `therefore21600`C will produce Hg `=(1)/(2xx96500)xx21600`mole=0.112 mole

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How many moles of mercury will be produced by electrolysing 1.0 M `Mg(NO_(3))_(2)` solution with a current of 2.00 A for 3 hours? `[Hg(NO_(3))_(2)=200.6" g "mol^(-1)]`

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