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InterviewSolution
| 1. |
how much CO2 is required to precipitate 10g caco3 from ca(oh)2 |
| Answer» Ans:4.4gCa(OH)2 + CO2 gives CaCO3 + H2OFrom stoichiometry,we can understand that\'1 mole of Ca(OH)2 (molar mass:74g)\' reacts with \'1 mole of CO2 (molar mass :44g)\' to give \'1 mole each of CaCO3 and H2O. (molar mass:100g and 18g respectively)\'Or,44g of CO2 gives 100g of CaCO3.Hence,to precipitate 1g of CaCO3, 44/100g=0.44g of CO2 is required. (Unitary method)Therefore, 10g of CaCO3 is obtained from 0.44*10=4.4g of CO2... | |