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How to derive the value of (small) g as :- Step by step explanation. Please. Don't write if you don't know the correct answer. ​

Answer» <html><body><p>ve:-<a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of g on earth's surface. (9.8m/s²)Derivation:-•Mass of earth (Mₑ) = 6×10²⁴kg•Radius of earth (Rₑ) = 6.4×10⁶m•Value of G = 6.67×10⁻¹¹ Nm²/kg²Now,we <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that:-=&gt; g = GM/R²Thus,value of g on earth's surface will be:-=&gt;gₑ = GMₑ/R²ₑ=&gt;gₑ = 6.67×10⁻¹¹×6×10²⁴/(6.4×10⁶)²=&gt;gₑ = 6.67×10⁻¹¹×6×10²⁴/6.4×10⁶×6.4×10⁶=&gt;gₑ = (6.67×6)/(6.4×6.4)×10⁻¹¹⁺²⁴⁻⁶⁻⁶=&gt;gₑ = 40.02/40.96×10=&gt;gₑ = 0.98×10=&gt;gₑ = 9.8m/s²Hence,derived !!!Some Extra <a href="https://interviewquestions.tuteehub.com/tag/information-1043838" style="font-weight:bold;" target="_blank" title="Click to know more about INFORMATION">INFORMATION</a>:-•The value of g at the surface of earth is 9.8m/s² on an average.•The value of g decreases with height.•The value of g decreases with depth.•The value of g is more at poles and less at equator.•The value of g is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> at the centre of the earth.</p></body></html>


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