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How to derive the value of (small) g as :- Step by step explanation. Please. Don't write if you don't know the correct answer. |
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Answer» ve:-VALUE of g on earth's surface. (9.8m/s²)Derivation:-•Mass of earth (Mₑ) = 6×10²⁴kg•Radius of earth (Rₑ) = 6.4×10⁶m•Value of G = 6.67×10⁻¹¹ Nm²/kg²Now,we KNOW that:-=> g = GM/R²Thus,value of g on earth's surface will be:-=>gₑ = GMₑ/R²ₑ=>gₑ = 6.67×10⁻¹¹×6×10²⁴/(6.4×10⁶)²=>gₑ = 6.67×10⁻¹¹×6×10²⁴/6.4×10⁶×6.4×10⁶=>gₑ = (6.67×6)/(6.4×6.4)×10⁻¹¹⁺²⁴⁻⁶⁻⁶=>gₑ = 40.02/40.96×10=>gₑ = 0.98×10=>gₑ = 9.8m/s²Hence,derived !!!Some Extra INFORMATION:-•The value of g at the surface of earth is 9.8m/s² on an average.•The value of g decreases with height.•The value of g decreases with depth.•The value of g is more at poles and less at equator.•The value of g is ZERO at the centre of the earth. |
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