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How will you calculate the length of the S period.

Answer» <html><body><p></p>Solution :According to Newton.s second <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> <br/>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= (dp)/(dt)` i.e. `dp = F dt` <br/><a href="https://interviewquestions.tuteehub.com/tag/integrate-2131645" style="font-weight:bold;" target="_blank" title="Click to know more about INTEGRATE">INTEGRATE</a> it over a time interval from `t_1 ` to `t_f`<br/>`int_i^f dp = int_(t_1)^(t_f)F dt` <br/>`P_f - P_i = int_(t_1)^(t_2) F. dt` <br/>`P_1 to` initial momentum of the object at `t_1`<br/>`P_f to ` Final momentum of the object at `t_f` <br/>`P_f - P_i = <a href="https://interviewquestions.tuteehub.com/tag/deltap-2053537" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAP">DELTAP</a>=` <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in momentum during the time interval `Deltat. int_(t_1)^(t_f) F dt` = J is called the impulse. <br/>If the force is constant over the time interval `Deltat`, then<br/>`int_(t_1)^(t_f) F dt = F int_(t_1)^(t_f) dt = F(t_f - t_i) = F Deltat`<br/>`J = F Deltat= Deltap` <br/>Hence the proof.</body></html>


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