1.

How will you distinguish `1^(@)` and `2^(@)` hydroxyl groups present in glucose? Explain the reactions.

Answer» Glucose forms a pentacetyl derivative on reaction with acetic anhydribe. This shows the presence of five -OH groups in its molecule. With a strong oxidising agent like conc. `HNO_(3)`, glucose is oxidised to a dicarboxylic acid saccharic acid with six carbon atoms. This shows that its molecule has a primary alcoholic group. We may conclude that it has one primary alcoholic group and four secondary alcoholic group in its molecule.


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