InterviewSolution
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InterviewSolution
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How would you account for the following: of the `d^(4)` species `Cr^(2+)` is strongly reducing while manganese(III) is strongly oxiding. Cobalt(II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised. The `D^(1)` configuration is very unstable in ions. |
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Answer» Correct Answer - (i) `E^(0)` value for `Cr^(3+)//Cr^(2+)` is negative `(-0.41V)` whereas `E^(0)` value for `Mn^(3+)//Mn^(2+)` is positve `(+1.57V)` Hence, `Cr^(2+)` ions can easily undergo oxidation to give `Cr^(3+)` ions and , therefore , act as strong reducing agent whereas `Mn^(3+)` can easily undergo reduction to give `Mn^(2+)` and hence acts as oxidizing agent (ii) `3d^(6)` has higher `CFSE` `(C ) The ions with `D^(1)` configuration have the tendency to lose the only electron present in d-subshell to acquire stable `d^(0)` configuration . Hence , they are unstable and undergo oxidation agent. |
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