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I. `CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH` II. `CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3)` III. `CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3)` IV. `CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH` V. `CH_(3) - CH_(2) - O - CH_(2) - CH_(3)` VI. `CH_(3) - O - CH_(2) - CH_(2) - CH_(3)` VII. `CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3)` Which of the above compounds form pairs of metamers ? |
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Answer» Metamerism arises due to different alkyl chains on either side of the functional group in the molecule. In the given structure V and VI or VI and VII form a pair of metamers because they differ in carbon atoms on the either side of the functional group, i.e., O-atom. `{:(V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3)" ethoxy ethane"),(VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) " methoxy propane"):} } "Metamers"` `{:(VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) " methoxy propane"),(VII. CH_(3) - O - underset(underset(CH_(3))(|))(CH) - CH_(3) " methoxy isopropane" ):} } "Metamers"` |
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