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(i) In the arrangement shown in the figure the coefficient of friction between the 2 kg block and the vertical wall is mu= 0.5. A constant horizontal force of 40 N keeps the block pressed against the wall. The spring has a natural length of 1.0 m and its force constant is k = 400 Nm^(–1). What should be the height h of the block above the horizontal floor for it to be in equilibrium. The spring is not tied to the block. (ii) A block of mass M is pressed against a rough vertical wall by applying a force F making anangle of theta with horizontal (as shown in figure). Coefficient of friction between the wall and the block is mu = 0.75. (a) If F = 2 Mg, find the range of values of theta so that the block does not slide [Take "tan" 37^(@) = 0.75, "sin" 24^(@) = 0.4] (b) Find the maximum value of theta above which equilibrium is not possible for any magnitude of force F. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> <a href="https://interviewquestions.tuteehub.com/tag/le-540308" style="font-weight:bold;" target="_blank" title="Click to know more about LE">LE</a> <a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>^(@)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/37-309797" style="font-weight:bold;" target="_blank" title="Click to know more about 37">37</a>^(@)`</body></html> | |