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(i) The energy associated with the first orbit in the hydrogen atom is -2.18 × 10-18 atom-1 . What is the energy associated with the fourth orbit? (ii) Calculate the radius of Bohr's third orbit for hydrogen atom. |
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Answer» (i) E = -2.18 x 10-18 x \(\frac{z^2}{n^2}J\) atom-1 For H − atom, z = 1 value of n for fourth orbit = 4 \(\therefore\) E = -2.18 x 10-18\(\frac{(1)^2}{(4)^2}\) = \(\frac{-2.18\times10^{-18}}{16}\) = -0.136 x 10-18 =-1.36 x 10-19 J (ii) Radius of third orbit for H-atom rn = \(\frac{52.9n^2}{z}\) r3 = \(\frac{52.9\times(3)^2}{1}\) = 52.9 × 9 = 476.1 pm |
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