1.

(i) The energy associated with the first orbit in the hydrogen atom is -2.18 × 10-18 atom-1 . What is the energy associated with the fourth orbit? (ii) Calculate the radius of Bohr's third orbit for hydrogen atom.

Answer»

(i) E = -2.18 x 10-18\(\frac{z^2}{n^2}J\) atom-1

For H − atom, z = 1

value of n for fourth orbit = 4

\(\therefore\) E = -2.18 x 10-18\(\frac{(1)^2}{(4)^2}\)

\(\frac{-2.18\times10^{-18}}{16}\)

= -0.136 x 10-18

=-1.36 x 10-19 J

(ii) Radius of third orbit for H-atom

rn\(\frac{52.9n^2}{z}\)

r3\(\frac{52.9\times(3)^2}{1}\)

= 52.9 × 9

= 476.1 pm



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