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                                    (i) Which of the following correspondences can be called a function? (A) f(x)=x^(3),{-1,0,1}to{0,1,2,3} (B)f(x)=+-sqrt(x),{0,1,4}to{-2,-1,0,1,2} (C)f(x)=sqrt(x),{0,1,4}to{0,1,4}to{-2,-1,0,1,2} (D) f(x)=-sqrt(x),{0,1,4}to{-2,-1,0,1,2} (ii) Which of the following pictorial diagrams represent the function | 
                            
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Answer» Solution :(i) `f(x)` in (C) and (D) are functions as definition of function is satisfied. While in case of (A) the given relation is not a function, as `f(-1)!in` 2nd SET. Hence definition of function is not satisfied. While in case of (B), the given relation is not a function as `f(1)=+-1` and `f(4)=+-2` i.e. element 1 as well as 4 in 1st set is related with TWO ELEMENTS of 2nd set. Hence definition of function is not satisfied.  (ii) B and D. In (A) ONE element of domain has no image, while in (C) one element of 1st set has two images in 2nd set  | 
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