InterviewSolution
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InterviewSolution
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Identify the complex which are expected to be coloured Explain (a) `[Ti(NO_(3))_(4)]` (b) `[Cu(NCH_(3))]^(o+) BF_(4)^(Θ)` (c ) `[Cr(NH_(3))_(6)]^(3+) 3CI^(Θ)` (d) `K_(3)[VF_(6)]` . |
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Answer» `[Ti(NO_(3))_(4)]` The oxidation state of `Ti` is `+4` The atomic number of titanium is `22` `Ti =[Ar] 3d^(2) 4s^(2)` `Ti^(4+) =[Ar]` No unpaired electrons So it is colourless (ii) `[Cu(NCCH_(3))]^(4) BF_(4) Θ` The oxidation state of `Cu` is `+1` The atomic number of copper is 28 `Cu =[Ar] 3d^(10) 4s^(1)` `Cu = [Ar] 3d^(9)` No unpaired electrons So it is colouless (iii) `[Cr(NH_(3))_(6)]^(3+)3CI^(Θ)` The oxidation sate of `Cr` is `+23` The atomic number of chromium is 24 `Cr[Ar]3d^(10) 4s^(1)` `Cr = [Ar] 3d^(8)` It has 3 unpaired elctrons So it is coloured (iv) `K_(3)[VE_(6)]` The oxidation state of `V` is `+3` The atomic number of vanadium is `+3` The atomic number of vanatium is `+3` `V =[Ar]3d^(3) 4s^(2)` `V^(3+) = [Ar]3d` It has 3 unpaired electrons So it coloured . |
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