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Identify the substance oxidized and the subsidized reducing in the given equation MnO2 + 4HCI=MnCI2+CO2+ 2H2O explain which is the reducing agent and the oxidant agent |
Answer» <html><body><p><strong>Answer:</strong></p><p>In the reaction MnO2 + 4HCl -> <a href="https://interviewquestions.tuteehub.com/tag/mncl2-2178955" style="font-weight:bold;" target="_blank" title="Click to know more about MNCL2">MNCL2</a> + Cl2 + 2H2O , Cl (<a href="https://interviewquestions.tuteehub.com/tag/chlorine-915874" style="font-weight:bold;" target="_blank" title="Click to know more about CHLORINE">CHLORINE</a>) is the <a href="https://interviewquestions.tuteehub.com/tag/substance-1231528" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTANCE">SUBSTANCE</a> which is <a href="https://interviewquestions.tuteehub.com/tag/oxidized-2906544" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDIZED">OXIDIZED</a> from the HCl, and it is the reducing agent for the MnO2 as well. As Cl is the oxidized substance in HCl, thus it is the oxidizing agent in the reaction</p></body></html> | |