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If 0.5 mole of `BaCl_(2)` mixed with 0.20 mole of `Na_(3) PO_(4)` the maximum number of moles of `Ba_(3)(PO)_(2)` then can be formed isA. 0.1B. 0.2C. 0.5D. 0.7 |
Answer» Correct Answer - A `underset(2 "mol")(3 BaCl_(2)) + underset(2 "mol")(2Na_(3)PO_(4)) rarr underset(6 "mol")(6NaCl) + underset(1 "mol")(Ba_(3) (PO_(4))_(2))` Given `implies 0.5 "mol of" BaCl_(2)` and `0.2 "mol of" Na_(3)PO_(4)` Find the limiting reagent: `2 "mol of" Na_(3)PO_(4) implies 2 "mol of" BaCl_(2)` `0.2 "mol of" Na_(3)PO_(4) implies 0.3 "mol of" BaCl_(2)` `:. Na_(3)PO_(4)` is the limiting reagent `:. "mol of" Na_(3)PO_(4) implies "mol of" Ba_(3) (PO_(4))_(2)` `0.2 "mol" of NaPO_(4) implies 0.1 "mol of" Ba_(3)(PO_(4))_(2)` |
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